Wednesday, August 31, 2011

AP Chem blog 3

Calculate the mass percent of each element in glucose (C6H12O6).
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14 comments:

  1. NayiriSeptember 1, 2011 at 6:06 PM

    6 Carbon: 12.01x 6= 72.06g
    12 Hydrogen: 12x 1.01= 12.02g
    6 Oxygen: 6x16=96g

    72.06+12.02+96= 180.08g

    72.06g/180.08g= 40.1% carbon

    12.02g/180.08g= 6.6% hydrogen

    96g/180.08g= 53.3% oxygen

    ReplyDelete
  2. AnonymousSeptember 1, 2011 at 8:37 PM

    6Carbons 6x12.01=72.06g
    12Hydrogens 12x1.01=12.02g
    6Oxygens 6x16.00=96.00g
    C6H12O6 molar mass 72.06g+12.02g+96.00g=180.08g

    72.06g/180.08gx100=40.01%Carbon
    12.02g/180.08gx100=6.675%Hydrogen
    96.0g/180.08gx100=53.31%Oxygen

    ReplyDelete
  3. Mr. PSeptember 2, 2011 at 2:17 AM

    Nice job Nayiri and Katrine! I am happy to see you staying on top of things! Keep it up!

    ReplyDelete
  4. varak ghazarianSeptember 2, 2011 at 12:22 PM

    6 C: 12.01*6=72.06
    12 H: 1.01*12=12.12
    6 O: 16.00*6=96.00

    96.00+72.06+12.12=180.08

    C: 72.06/180.08=40.0%
    H: 12.12/180.08=6.7%
    O: 96.00/180.08=53.3%

    ReplyDelete
  5. Garni TerterianSeptember 3, 2011 at 10:38 AM

    C: 6*12.01= 72.06g
    H: 12*1.01 = 12.12g
    O: 6*16.00 = 96.00g

    Molar Mass = 72.06+12.12+96.00 = 180.18 g/mol

    C: 72.06/180.18 *100 =40.0%
    H: 12.12/180.18 *100 =6.7%
    O: 96.00/180.18 *100 =53.3%

    ReplyDelete
  6. Hasmik.September 3, 2011 at 12:12 PM

    6 Carbons = 6 x 12.01 = 72.06 g C
    12 Hydrogens = 12 x 1.01 = 12.12 g H
    6 Oxygens = 6 x 16.00 = 96.00 g O

    Molar Mass of Glucose = 72.06 + 12.02 + 96.00 = 180.18 g/mol

    Carbon: 72.06 / 180.18 x 100 = 39.99% C
    Hydrogen: 12.12 / 180.18 x 100 = 6.727% H
    Oxygen: 96.00 / 180.18 x 100 = 53.28% O

    ReplyDelete
  7. AnonymousSeptember 3, 2011 at 1:37 PM

    6 Carbon: 6 x 12.01=72.06 grams of carbon
    12 Hydrogen: 12 x 1.01=12.12 grams of hydrogen
    6 Oxygen: 6 x 16.00=96.00 grams of oxygen
    Molar Mass of C6H12O6: 72.06 g C + 12.12 g H + 96.00 g O= 180.18 g C6H12O6

    Mass Percent of Carbon: (72.06 g C/180.18 g C6H12O6) x 100=39.99%
    Mass Percent of Hydrogen: (12.12 g H/180.18 g C6H12O6) x 100=6.730%
    Mass Percent of Oxygen: (96.00 g O/180.18 g C6H12O6) x 100=53.28%

    ReplyDelete
  8. AnonymousSeptember 4, 2011 at 1:16 PM

    6 C= 6 x 12.01 g/mol= 72.06 g/mol C
    12 H= 12 x 1.01 g/mol= 12.12 g/mol H
    6 O= 6 x 16.00 g/mol= 96.00 g/mol O
    MM of C6H12O6= 180.18 g/mol C6H12O6
    Mass % C= (72.06 g/mol C)/(180.18 g/mol C6H12O6) x 100= 39.99 % ~ 40.00 %
    Mass % H= (12.12 g/mol H)(180.18 g/mol C6H12O6) x 100= 6.73 %
    Mass % O= (96.00 g/mol O)/(180.18 g/mol C6H12O6) x 100= 53.28 %

    ReplyDelete
  9. AnnieSeptember 4, 2011 at 9:46 PM

    6 C: 12.01x6=72.06 grams of carbon
    12 H: 1.01x12=12.12 grams oh hydrogen
    6 O: 16.00x6=96.00 grams of oxygen

    MM of glucose: 96.00+72.06+12.12=180.08 g/mol

    Mass % C: (72.06/180.08) x100 =40.0%
    Mass % H: (12.12/180.08) x100 =6.7%
    Mass % O: (96.00/180.08) x100 =53.3%

    ReplyDelete
  10. AnonymousSeptember 4, 2011 at 9:51 PM

    1 mole of C6H12O6 has a mass of...
    6 mole carbon x 12.01g/mol = 72.06 g carbon
    12 mole Hydrogen x 1.01g/mol = 12.12 g Hydrogen
    6 mole oxygen x 16.00 = 96.00 g Oxygen
    Molar Mass= 72.06g C + 12.12g H + 96.00g O = 180.18g C6H12O6

    Mass % of C: (72.06 g C/180.18 g C6H12O6) x 100= 39.99%

    Mass % of H: (12.12 g H/180.18 g C6H12O6) x 100= 6.730%

    Mass % of O: (96.00 g O/180.18 g C6H12O6) x 100= 53.28%

    ReplyDelete
  11. ShauntikSeptember 5, 2011 at 7:01 PM

    6 Carbons - 12.01 x 6 = 72.06g
    12 Hydrogens - 1.01 x 12 = 12.12g
    6 Oxygens - 16 x 6 = 96g
    96 + 12.02 + 72.06 = 180.08g is MM of Glucose

    Carbon - 72.06/180.18 x 100 = 39.99% C
    Hydrogen - 12.12/180.18 x 100 = 6.727% H
    Oxygen - 96.00/180/18 x 100 = 53.28%

    ReplyDelete
  12. Michael C.September 5, 2011 at 10:42 PM

    C 6x12.01= 72.06g
    H 12x1.01 = 12.12g
    O 6x16.00 = 96.00g
    = 72.06+12.12+96.00 = 180.18 g/mol(molar mass)

    C 72.06/180.18x100=39.99%C
    H 12.12/180.18x100=6.727%H
    O 96.00/180.18x100=53.28%O

    ReplyDelete
  13. Alexa KovacsSeptember 5, 2011 at 11:36 PM

    to find the mass percent first you have to find the total mass of C6H12O6

    6 carbons: 12.01 g/mol * 6 mol C= 72.06 g C
    12 hydrogens: 1.01 g/mol * 12 mol H= 12.12 g H
    6 oxygens: 16.00 g/mol * 6 mol O= 96.00 g O
    total mass of C6H12O6= (72.06 g C) + (12.12 g H) + (96.00 g O) = 180.18 g

    carbon: 72.06 g C/ 180.18 g C6H12O6 * 100= 39.99% C
    hydrogen: 12.12 g H/ 180.18 g C6H12O6 * 100= 6.73% H
    oxygen: 96.00 g O/ 180.18 g C6H12O6 * 100= 53.28% O

    to make 100% C6H12O6

    ReplyDelete
  14. AlecSeptember 6, 2011 at 9:00 AM

    6Carbons 6x12.01=72.06g
    12Hydrogens 12x1.01=12.02g
    6Oxygens 6x16.00=96.00g
    C6H12O6 molar mass 72.06g+12.02g+96.00g=180.08g

    72.06g/180.08gx100=40.01%Carbon
    12.02g/180.08gx100=6.675%Hydrogen
    96.0g/180.08gx100=53.31%Oxygen

    ReplyDelete

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