a) diamagnetic since Li has 1 electron so Li2 will have 2 electrons and both will be paired. b) bond order is 1 because two pairs of electrons are bonding and none are antibonding, therefore (2-0)/2 is 1, and it exists. c) sp hybridized d) linear molecular structure e) since there are only one pair of bonding electrons and that pair is a single bond, there will therefore be 1 sigma and no pi bonds.
a) Li2 is diamagnetic, since it has a total of 2 valence electrons, and no unpaired electrons. b) Bond order= paired electrons-unpaired electrons= (2-0)/2= 1 So the molecule does exist. c) sp hybridization d) Linear molecular structure e) 1 sigma, 0 pi bonds
a. diamagnetic because it has 2 paired electrons. b. bond order is 2-0 /2 = 1. Therefore the species exists. c. sp d. linear e. 1 sigma bond and 0 pi bonds
a. paramagnetic because valence shell isn't filled.
ReplyDeleteb. Bond order is 1.
c. Hybridization=sp
d. molecular geometry=linear
e. 1 sigma bond, no pi bonds.
A) Paramagnetic because the valence shell is not complete.
ReplyDeleteB)bond order:1
C) sp
D) linear
E) 1 sigma bond no pi bonds
Li2 so 2 electrons
ReplyDeletea) diamagnetic since it has 2 electrons paired
b) bond order: 2-0 /2 = 1 yes it exists
c) sp
d) linear
e) 1 sigma bond 0 pi bonds
a. diamagnetic
ReplyDeleteb. 2-0/2= 1 yes it exists
c. sp
d. linear
e. 0 pi
a) diamagnetic since Li has 1 electron so Li2 will have 2 electrons and both will be paired.
ReplyDeleteb) bond order is 1 because two pairs of electrons are bonding and none are antibonding, therefore (2-0)/2 is 1, and it exists.
c) sp hybridized
d) linear molecular structure
e) since there are only one pair of bonding electrons and that pair is a single bond, there will therefore be 1 sigma and no pi bonds.
a. diamagnetic
ReplyDeleteb. (2-0)/2 =1bond order yes it exists
c. sp
d. linear
e. 1 sigma no pie
a) Li2 is diamagnetic, since it has a total of 2 valence electrons, and no unpaired electrons.
ReplyDeleteb) Bond order= paired electrons-unpaired electrons= (2-0)/2= 1 So the molecule does exist.
c) sp hybridization
d) Linear molecular structure
e) 1 sigma, 0 pi bonds
a) diamagnetic
ReplyDeleteb) 2-0 / 2 = 1 ; bond order is > 0, therefore this molecule exists
c) sp
d) linear
e) sigma = 1; pi = 0
a- diamagnetic
ReplyDeleteb- (bonding electrons - antibonding electrons)/2
(2-0)/2=1 This molecule exists
c- sp hybridized
d- linear
e- 1 sigma bond, 0 pi bonds
a. diamagnetic because it has 2 paired electrons.
ReplyDeleteb. bond order is 2-0 /2 = 1. Therefore the species exists.
c. sp
d. linear
e. 1 sigma bond and 0 pi bonds